If x1 and x2 are positive quantities, then the condition for the difference between the arithmetic mean and the geometric mean to be greater than 1 is

\({{\rm{x}}_1} + {{\rm{x}}_2} < 2{\rm{\;}}\left( {\sqrt {{{\rm{x}}_1}{{\rm{x}}_2}} + 1} \right)\)

\({{\rm{x}}_1} + {{\rm{x}}_2} > 2\sqrt {{{\rm{x}}_1}{{\rm{x}}_2}} \)

\(\sqrt {{{\rm{x}}_1}} + \sqrt {{{\rm{x}}_2}} > \sqrt 2 \)

\(\left| {\sqrt {{{\rm{x}}_1}} - \sqrt {{{\rm{x}}_2}} } \right| > \sqrt 2 \)

If x1 and x2 are positive quantities, then the condition for the diffe

1.	If x1 and x2 are positive quantities, then the condition for the difference between the arithmetic mean and the geometric mean to be greater than 1 is
A.	\({{\rm{x}}_1} + {{\rm{x}}_2} > 2\sqrt {{{\rm{x}}_1}{{\rm{x}}_2}} \)
B.	\(\sqrt {{{\rm{x}}_1}} + \sqrt {{{\rm{x}}_2}} > \sqrt 2 \)
C.	\(\left\| {\sqrt {{{\rm{x}}_1}} - \sqrt {{{\rm{x}}_2}} } \right\| > \sqrt 2 \)
D.	\({{\rm{x}}_1} + {{\rm{x}}_2} < 2{\rm{\;}}\left( {\sqrt {{{\rm{x}}_1}{{\rm{x}}_2}} + 1} \right)\)
Answer» D. \({{\rm{x}}_1} + {{\rm{x}}_2} < 2{\rm{\;}}\left( {\sqrt {{{\rm{x}}_1}{{\rm{x}}_2}} + 1} \right)\)

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If x1 and x2 are positive quantities, then the condition for the difference between the arithmetic mean and the geometric mean to be greater than 1 is

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