If $$ {x+3y-{2z over 4}}=6$$ , $$ {x+{2 over 3}}(2y+3z)=33$$ and $$ {1 over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?

If $$ {x+3y-{2z over 4}}=6$$ , $$ {x+{2 over 3}}(2y+3z)=33$$ and $$ {1

1.	If $$ {x+3y-{2z over 4}}=6$$ , $$ {x+{2 over 3}}(2y+3z)=33$$ and $$ {1 over 7}{(x+y+z)+2z=9}$$, then what is the value of $$ {46x+131y}$$?
A.	364
B.	414
C.	384
D.	464
Answer» C. 384