If we place a condenser at an angle of to the vertical, then the convective heat transfer coefficient can be represented as ____________

Question

If we place a condenser at an angle of   to the vertical, then the convective heat transfer coefficient can be represented as ____________

TuteeHUB · Accepted Answer

h_INC = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}tan alpha]^{0.25} )

TuteeHUB · Answer

hINC = 0.943   (0.943[  frac{K^3 p^2 g h_{fg}}{  mu L(T_{sat}   T_L)}sin u2061  alpha]^{0.25}  )

TuteeHUB · Answer

hINC = 0.943   (0.943[  frac{K^3 p^2 g h_{fg}}{  mu L(T_{sat}   T_L)}tan  alpha]^{0.25}  )

TuteeHUB · Answer

hINC = 0.943   (0.943[  frac{K^3 p^2 g h_{fg}}{  mu L(T_{sat}   T_L)}cos u2061  alpha]^{0.25}  )

TuteeHUB · Answer

hINC = 0.943   (0.943[  frac{K^3 p^2 g h_{fg}}{  mu L(T_{sat}   T_L)}cosec u2061  alpha]^{0.25}  )

1.	If we place a condenser at an angle of to the vertical, then the convective heat transfer coefficient can be represented as ____________
A.	h<sub>INC</sub> = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}sin u2061 alpha]^{0.25} )
B.	h<sub>INC</sub> = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}tan alpha]^{0.25} )
C.	h<sub>INC</sub> = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}cos u2061 alpha]^{0.25} )
D.	h<sub>INC</sub> = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}cosec u2061 alpha]^{0.25} )
Answer» B. h<sub>INC</sub> = 0.943 (0.943[ frac{K^3 p^2 g h_{fg}}{ mu L(T_{sat} T_L)}tan alpha]^{0.25} )

Discussion