If_V_=_2x2y_+_20z_‚Äö√Ñ√∂‚àö√ë‚àö¬®_4/(x2_+_y2),_find_the_density_at_A(6,_-2.5,_3)_in_nC/m2.$#

0.6373i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177j -0.531k

0.531i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177k

0.177i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.531k

0.531i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373k

If_V_=_2x2y_+_20z_‚Äö√Ñ√∂‚àö√ë‚àö¬®_4/(x2_+_y2

1.	If_V_=_2x²y_+_20z_‚Äö√Ñ√∂‚àö√ë‚àö¬®_4/(x²_+_y²),_find_the_density_at_A(6,_-2.5,_3)_in_nC/m².$#
A.	0.531i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177k
B.	0.6373i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177j -0.531k
C.	0.177i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.531k
D.	0.531i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177j ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.6373k
Answer» B. 0.6373i ‚Äö√Ñ√∂‚àö√ë‚àö¬® 0.177j -0.531k

If V = 2x2y + 20z – 4/(x2 + y2), find the density at A(6, -2.5, 3) in nC/m2.
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IF_THE_POTENTIAL_IS_GIVEN_BY,_V_=_10SIN_‚ÂÀ√≠‚ÄÖ√†√®_COS‚ÂÀ√¨‚ÀÖ√∫/R,_FIND_THE_DENSITY_AT_THE_POINT_P(2,_‚ÂÀ√¨‚ÀÖ√Ë/2,_0)?$#
If_V_=_2x2y_+_20z_‚Äö√Ñ√∂‚àö√ë‚àö¬®_4/(x2_+_y2),_find_the_density_at_A(6,_-2.5,_3)_in_nC/m2.$#
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