If \[u={{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0,\] \[v={{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0\] and \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}},\] then the curve \[u+kv=0\]is [MNR 1987]

If \[u={{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0,\] \[v={{a}_{2}}x+{{b}_{2}}y+

1.	If \[u={{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0,\] \[v={{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0\] and \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}},\] then the curve \[u+kv=0\]is [MNR 1987]
A.	The same straight line u
B.	Different straight line
C.	It is not a straight line
D.	None of these
Answer» B. Different straight line

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If \[u={{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0,\] \[v={{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0\] and \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{{{c}_{1}}}{{{c}_{2}}},\] then the curve \[u+kv=0\]is [MNR 1987]

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