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1. |
If the system of linear equationsX – 2y + kz = 12x + y + z = 23x – y – kz = 3has a solution (x, y, z), z ≠ 0, then (x, y) lies on the straight line whose equation is: |
A. | 3x – 4y – 1 = 0 |
B. | 4x – 3y – 4 = 0 |
C. | 4x – 3y – 1 = 0 |
D. | 3x – 4y – 4 = 0 |
Answer» C. 4x – 3y – 1 = 0 | |