If the roots of equation \[\frac{{{x}^{2}}-bx}{ax-c}=\frac{m-1}{m+1}\]are equal but opposite in sign, then the value of \[m\] will be [RPET 1988, 2001; MP PET 1996, 2002; Pb. CET 2000]

If the roots of equation \[\frac{{{x}^{2}}-bx}{ax-c}=\frac{m-1}{m+1}\]

1.	If the roots of equation \[\frac{{{x}^{2}}-bx}{ax-c}=\frac{m-1}{m+1}\]are equal but opposite in sign, then the value of \[m\] will be [RPET 1988, 2001; MP PET 1996, 2002; Pb. CET 2000]
A.	\[\frac{a-b}{a+b}\]
B.	\[\frac{b-a}{a+b}\]
C.	\[\frac{a+b}{a-b}\]
D.	\[\frac{b+a}{b-a}\]
Answer» B. \[\frac{b-a}{a+b}\]