If the laminar flow of the fluid having the viscosity μ is flowing through the pipe of the diameter D. Pressure gradient in the flow is $\left( { - \frac{{\partial p}}{{\partial x}}} \right)$.What is the average velocity of flow? .

Question

TuteeHUB · Accepted Answer

$V = \frac{1}{{8\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}$

TuteeHUB · Answer

$V = \frac{1}{{32\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}$

TuteeHUB · Answer

$V = \frac{1}{{16\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}$

TuteeHUB · Answer

$V = \frac{1}{{4\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}$

1.	If the laminar flow of the fluid having the viscosity μ is flowing through the pipe of the diameter D. Pressure gradient in the flow is \(\left( { - \frac{{\partial p}}{{\partial x}}} \right)\).What is the average velocity of flow? .
A.	\(V = \frac{1}{{32\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}\)
B.	\(V = \frac{1}{{8\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}\)
C.	\(V = \frac{1}{{16\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}\)
D.	\(V = \frac{1}{{4\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}\)
Answer» B. \(V = \frac{1}{{8\mu }}\left( { - \frac{{\partial p}}{{\partial x}}} \right){D^2}\)

If the laminar flow of the fluid having the viscosity μ is flowing through the pipe of the diameter D. Pressure gradient in the flow is \(\left( { - \frac{{\partial p}}{{\partial x}}} \right)\).What is the average velocity of flow? .

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