If the imaginary part of \(\frac{{2z + 1}}{{iz + 1}}\) is – 2, the – McqOptions

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1.	If the imaginary part of \(\frac{{2z + 1}}{{iz + 1}}\) is – 2, then the locus of the point z in the complex plane is
A.	x + 2y – 2 = 0
B.	2x + y – 2 = 0
C.	x – 2y – 2 = 0
D.	x + 2y + 2 = 0
Answer» B. 2x + y – 2 = 0

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