If the equation of a circle is ax2 + (2a - 3)y2 - 4x - 1 = 0, then its – McqOptions

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1.	If the equation of a circle is ax2 + (2a - 3)y2 - 4x - 1 = 0, then its centre is:
A.	(1, 1)
B.	(2, 0)
C.	\(\left( {\frac{2}{3},0} \right)\)
D.	\(\left( { - \frac{2}{3},0} \right)\)
Answer» D. \(\left( { - \frac{2}{3},0} \right)\)

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