Equation of the common tangent, with positive slope, to the circle x2 – McqOptions

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1.	Equation of the common tangent, with positive slope, to the circle x2 + y2 - 8x = 0 as well as to the hyperbola \(\rm \frac{x^2}{9}-\frac{y^2}{4}=1\), is:
A.	\(\rm2x-\sqrt{5}y-20=0\)
B.	\(\rm 2x-\sqrt{5}y + 4 = 0\)
C.	3x - 4y + 8 = 0
D.	4x - 3y + 4 = 0
Answer» C. 3x - 4y + 8 = 0

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