If the 6-digit number 479xyz is exactly divisible by 7, 11 and 13, the – McqOptions

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1.	If the 6-digit number 479xyz is exactly divisible by 7, 11 and 13, then the product of the digits x, y and z will be:
A.	1001
B.	794
C.	252
D.	479
Answer» D. 479

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