1.

If \[\tan \alpha ,\tan \beta \]are the roots of the equation \[{{x}^{2}}+px+q=0\text{  }(p\ne 0),\] then

A. \[{{\sin }^{2}}(\alpha +\beta )+p\sin (\alpha +\beta )\cos (\alpha +\beta )+q{{\cos }^{2}}(\alpha +\beta )=q\]
B. \[\tan (\alpha +\beta )=\frac{p}{q-1}\]
C. \[\cos (\alpha +\beta )=1-q\]
D. \[\sin (\alpha +\beta )=-p\]
Answer» C. \[\cos (\alpha +\beta )=1-q\]


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