If sum of n terms of an arithmetical progression is 5n2 - 3n, then its

1.	If sum of n terms of an arithmetical progression is 5n2 - 3n, then its pth term is.
A.	10p + 8
B.	10p - 8
C.	10p + 3
D.	10p - 3
Answer» C. 10p + 3

Discussion

No Comment Found

Related MCQs

If 3rd, 8th and 13th terms of a GP are p, q and r respectively, then which one of the following is correct?
Let a1, a2….a30 be an A.P\(S = \mathop \sum \limits_{i = 1}^{30} {a_i}{\rm{\;and\;}}T = \mathop \sum \limits_{i = 1}^{15} {a_{\left( {2i - 1} \right)}}\)If a5 = 27 and S – 2T = 75. Then a10 is equal to:
If 19th term of a non-zero A.P. is zero, then its (49th term) : (29th term) is:
If \({S_n} = nP + \frac{{n\left( {n - 1} \right)Q}}{2}\), where Sn denotes the sum of the first n terms of an AP, then the common difference is
If p, q, r, s are in G.P., then \(\frac{1}{{{p^2} + {q^2}}}\), \(\frac{1}{{{q^2} + {r^2}}}\), \(\frac{1}{{{r^2} + {s^2}}}\) are in
If a, b > 0, then the maximum value of \(\dfrac{a^3b}{(a + b)^4}\)is:
If the nth term of an AP be (2n - 1), then the sum of its first n terms will be:
If the geometric mean of two numbers is 6.0 and the arithmetic mean is 6.5, then the difference of squares of these numbers is
Let Tr be the rth term of an AP for r = 1, 2, 3, …… If for some distinct positive integers m and n we have Tm = 1/n and Tn = 1/m, then what is Tmn equal to?
Let a1, a2, a3,…. , a10 be in G.P. with ai > 0 for I = 1, 2, …, 10 and S be the set of pairs (r, k), r, k ∈ N (the set of natural numbers) for which\(\left| {\begin{array}{*{20}{c}}{{\rm{lo}}{{\rm{g}}_e}a_1^ra_2^k}&{{\rm{lo}}{{\rm{g}}_e}a_2^ra_3^k}&{{\rm{lo}}{{\rm{g}}_e}a_3^ra_4^k}\\{{\rm{lo}}{{\rm{g}}_e}a_4^ra_5^k}&{{\rm{lo}}{{\rm{g}}_e}a_5^\pi a_6^k}&{{\rm{lo}}{{\rm{g}}_e}a_6^ra_7^k}\\{{\rm{lo}}{{\rm{g}}_e}a_7^ra_8^k}&{{\rm{lo}}{{\rm{g}}_e}a_8^\pi a_9^k}&{{\rm{lo}}{{\rm{g}}_e}a_9^ra_{10}^k}\end{array}} \right| = 0\)Then the number of elements in S, is:

If sum of n terms of an arithmetical progression is 5n2 - 3n, then its pth term is.

Discussion

No Comment Found

Related MCQs

Reply to Comment