If $$\sqrt{3}+i=(a+ib)(c+id)$$, then $${{\tan }^{-1}}\left( \frac{b}{a} \right)+$$ $${{\tan }^{-1}}\left( \frac{d}{c} \right)$$ has the value

Question

TuteeHUB · Accepted Answer

$$n\pi -\frac{\pi }{3},n\in I$$

TuteeHUB · Answer

$$\frac{\pi }{3}+2n\pi ,n\in I$$

TuteeHUB · Answer

$$n\pi +\frac{\pi }{6},n\in I$$

TuteeHUB · Answer

$$2n\pi -\frac{\pi }{3},n\in I$$

1.	If \[\sqrt{3}+i=(a+ib)(c+id)\], then \[{{\tan }^{-1}}\left( \frac{b}{a} \right)+\] \[{{\tan }^{-1}}\left( \frac{d}{c} \right)\] has the value
A.	\[\frac{\pi }{3}+2n\pi ,n\in I\]
B.	\[n\pi +\frac{\pi }{6},n\in I\]
C.	\[n\pi -\frac{\pi }{3},n\in I\]
D.	\[2n\pi -\frac{\pi }{3},n\in I\]
Answer» C. \[n\pi -\frac{\pi }{3},n\in I\]

If \[\sqrt{3}+i=(a+ib)(c+id)\], then \[{{\tan }^{-1}}\left( \frac{b}{a} \right)+\] \[{{\tan }^{-1}}\left( \frac{d}{c} \right)\] has the value