1.

If Sₙ=4Sₙ₋₁+12n, where S₀=6 and S₁=7, find the solution for the recurrence relation.

A. aₙ=7(2ⁿ)−29/6n6ⁿ
B. aₙ=6(6ⁿ)+6/7n6ⁿ
C. aₙ=6(3ⁿ⁺¹)−5n
D. aₙ=nn−2/6n6ⁿ
Answer» C. aₙ=6(3ⁿ⁺¹)−5n


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