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1. |
If Sₙ=4Sₙ₋₁+12n, where S₀=6 and S₁=7, find the solution for the recurrence relation. |
A. | aₙ=7(2ⁿ)−29/6n6ⁿ |
B. | aₙ=6(6ⁿ)+6/7n6ⁿ |
C. | aₙ=6(3ⁿ⁺¹)−5n |
D. | aₙ=nn−2/6n6ⁿ |
Answer» C. aₙ=6(3ⁿ⁺¹)−5n | |