If \({\rm{X}} = \left[ {\begin{array}{*{20}{c}} 3&{ - 4}\\ 1&{ - 1} \end{array}} \right],{\rm{\;B}} = \left[ {\begin{array}{*{20}{c}} 5&2\\ { - 2}&1 \end{array}} \right]{\rm{\;and\;A}} = \left[ {\begin{array}{*{20}{c}} {\rm{p}}&{\rm{q}}\\ {\rm{r}}&{\rm{s}} \end{array}} \right]\)Satisfy the equation AX = B, then the matrix A is equal to

• A. \(\left[ {\begin{array}{*{20}{c}} { - 7}&{26}\\ 1&{ - 5} \end{array}} \right]\)
• B. \(\left[ {\begin{array}{*{20}{c}} 7&{26}\\ 4&{17} \end{array}} \right]\)
• C. \(\left[ {\begin{array}{*{20}{c}} { - 7}&{ - 4}\\ {26}&{13} \end{array}} \right]\)
• D. \(\left[ {\begin{array}{*{20}{c}} { - 7}&{26}\\ { - 6}&{23} \end{array}} \right]\)