If \(\rm f(x) = \left\{ \begin{matrix} \rm \dfrac{x-x^2}{2x}; & \rm x \ne 0 \\ \rm K; & \rm x = 0 \end{matrix}\right.\) is a continuous function at x = 0, then the value of k is:

If \(\rm f(x) = \left\{ \begin{matrix} \rm \dfrac{x-x^2}{2x}; & \rm x

1.	If \(\rm f(x) = \left\{ \begin{matrix} \rm \dfrac{x-x^2}{2x}; & \rm x \ne 0 \\ \rm K; & \rm x = 0 \end{matrix}\right.\) is a continuous function at x = 0, then the value of k is:
A.	2
B.	\(\dfrac12\)
C.	1
D.	None of these
Answer» C. 1

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If \(\rm f(x) = \left\{ \begin{matrix} \rm \dfrac{x-x^2}{2x}; & \rm x \ne 0 \\ \rm K; & \rm x = 0 \end{matrix}\right.\) is a continuous function at x = 0, then the value of k is:

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