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1. |
If one root of the equation \[a{{x}^{2}}+bx+c=0\]the square of the other, then\[a{{(c-b)}^{3}}=cX\], where X is |
A. | \[{{a}^{3}}+{{b}^{3}}\] |
B. | \[{{(a-b)}^{3}}\] |
C. | \[{{a}^{3}}-{{b}^{3}}\] |
D. | None of these |
Answer» C. \[{{a}^{3}}-{{b}^{3}}\] | |