If n is a natural number and n = $${p_1}^{{x_1}}$$$${p_2}^{{x_2}}$$$${p_3}^{{x_3}}$$where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :

$\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$

${x_1} \times {x_2} \times {x_3}$$

If n is a natural number and n = $${p_1}^{{x_1}}$$$${p_2}^{{x_2}}$$$${

1.	If n is a natural number and n = $${p_1}^{{x_1}}$$$${p_2}^{{x_2}}$$$${p_3}^{{x_3}}$$where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :
A.	${x_1} + {x_2} + {x_3}$$
B.	${x_1} \times {x_2} \times {x_3}$$
C.	$\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$
D.	one of these
Answer» C. $\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$