If \(\mathop {{\rm{lim}}}\limits_{{\rm{x}} \to 1} \frac{{{{\rm{x}}^4}

1.	If \(\mathop {{\rm{lim}}}\limits_{{\rm{x}} \to 1} \frac{{{{\rm{x}}^4} - 1}}{{{\rm{x}} - 1}} = \mathop {{\rm{lim}}}\limits_{{\rm{x}} \to {\rm{k}}} \frac{{{{\rm{x}}^3} - {{\rm{k}}^3}}}{{{{\rm{x}}^2} - {{\rm{k}}^2}}}\), then k is:
A.	8/3
B.	3/8
C.	3/2
D.	4/3
Answer» B. 3/8

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If \(\mathop {{\rm{lim}}}\limits_{{\rm{x}} \to 1} \frac{{{{\rm{x}}^4} - 1}}{{{\rm{x}} - 1}} = \mathop {{\rm{lim}}}\limits_{{\rm{x}} \to {\rm{k}}} \frac{{{{\rm{x}}^3} - {{\rm{k}}^3}}}{{{{\rm{x}}^2} - {{\rm{k}}^2}}}\), then k is:

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