1.

If \[l(m,\,n)=\int_{0}^{1}{{{t}^{m}}{{(1+t)}^{n}}dt,}\] then the expression for \[l(m,\,n)\] in terms of \[l(m+1,\,\,n-1)\] is [IIT Screening 2003]

A. \[\frac{{{2}^{n}}}{m+1}-\frac{n}{m+1}l(m+1,\,n-1)\]
B. \[\frac{n}{m+1}l(m+1,\,n-1)\]
C. \[\frac{{{2}^{n}}}{m+1}+\frac{n}{m+1}l(m+1,\,n-1)\]
D. \[\frac{m}{n+1}l(m+1,\,n-1)\]
Answer» B. \[\frac{n}{m+1}l(m+1,\,n-1)\]


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