If \(\left| {\begin{array}{*{20}{c}} {a - b - c}&{2a}&{2a}\\ {2b}&{b - c - a}&{2b}\\ {2c}&{2c}&{c - a - b} \end{array}} \right| = \left( {a + b + c} \right){(x + a + b + c)^2}\), x ≠ 0 and a + b + c ≠ 0, then ‘x’ is equal to:

If \(\left| {\begin{array}{*{20}{c}} {a - b - c}&{2a}&{2a}\\ {2b}&{b -

1.	If \(\left\| {\begin{array}{*{20}{c}} {a - b - c}&{2a}&{2a}\\ {2b}&{b - c - a}&{2b}\\ {2c}&{2c}&{c - a - b} \end{array}} \right\| = \left( {a + b + c} \right){(x + a + b + c)^2}\), x ≠ 0 and a + b + c ≠ 0, then ‘x’ is equal to:
A.	abc
B.	-(a + b + c)
C.	2(a + b + c)
D.	-2(a + b + c)
Answer» E.

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If \(\left| {\begin{array}{*{20}{c}} {a - b - c}&{2a}&{2a}\\ {2b}&{b - c - a}&{2b}\\ {2c}&{2c}&{c - a - b} \end{array}} \right| = \left( {a + b + c} \right){(x + a + b + c)^2}\), x ≠ 0 and a + b + c ≠ 0, then ‘x’ is equal to:

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