If \(\left[ {\begin{array}{*{20}{c}} 1&1\\ 0&1 \end{array}} \right]\cdot\left[ {\begin{array}{*{20}{c}} 1&2\\ 0&1 \end{array}} \right]\cdot\left[ {\begin{array}{*{20}{c}} 1&3\\ 0&1 \end{array}} \right] \ldots \ldots \ldots \left[ {\begin{array}{*{20}{c}} 1&{{\rm{n}} - 1}\\ 0&1 \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 1&{78}\\ 0&1 \end{array}} \right],\;\)then the inverse of \(\left[ {\begin{array}{*{20}{c}} 1&{\rm{n}}\\ 0&1 \end{array}} \right]\) is:

• A. \(\left[ {\begin{array}{*{20}{c}} 1&0\\ {12}&1 \end{array}} \right]\)
• B. \(\left[ {\begin{array}{*{20}{c}} 1&{ - 13}\\ 0&1 \end{array}} \right]\)
• C. \(\left[ {\begin{array}{*{20}{c}} 1&{ - 12}\\ 0&1 \end{array}} \right]\)
• D. \(\left[ {\begin{array}{*{20}{c}} 1&0\\ {13}&1 \end{array}} \right]\)