If \[{{I}_{n}}=\int_{0}^{\infty }{{{e}^{-x}}{{x}^{n-1}}dx,}\] then \[\ – McqOptions

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1.	If \[{{I}_{n}}=\int_{0}^{\infty }{{{e}^{-x}}{{x}^{n-1}}dx,}\] then \[\int_{0}^{\infty }{{{e}^{-\lambda x}}{{x}^{n-1}}dx=}\]
A.	\[\lambda {{I}_{n}}\]
B.	\[\frac{1}{\lambda }{{I}_{n}}\]
C.	\[\frac{{{I}_{n}}}{{{\lambda }^{n}}}\]
D.	\[{{\lambda }^{n}}{{I}_{n}}\]
Answer» D. \[{{\lambda }^{n}}{{I}_{n}}\]

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