1.

If \[f(x)=3{{e}^{{{x}^{2}}}}\],then \[f'(x)-2xf(x)+\frac{1}{3}f(0)-f'(0)=\]

A. 0
B. 1
C. \[\frac{7}{3}{{e}^{{{x}^{2}}}}\]
D. None of these
Answer» C. \[\frac{7}{3}{{e}^{{{x}^{2}}}}\]


Discussion

No Comment Found