If from mean value theorem, \[f'({{x}_{1}})=\frac{f(b)-f(a)}{b-a}\], then [MP PET 1999]

If from mean value theorem, \[f'({{x}_{1}})=\frac{f(b)-f(a)}{b-a}\], t

1.	If from mean value theorem, \[f'({{x}_{1}})=\frac{f(b)-f(a)}{b-a}\], then [MP PET 1999]
A.	\[a<{{x}_{1}}\le b\]
B.	\[a\le {{x}_{1}}<b\]
C.	\[a<{{x}_{1}}<b\]
D.	\[a\le {{x}_{1}}\le b\]
Answer» D. \[a\le {{x}_{1}}\le b\]

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If from mean value theorem, \[f'({{x}_{1}})=\frac{f(b)-f(a)}{b-a}\], then [MP PET 1999]

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