If \[\frac{z-i}{z+i}(z\ne -i)\] is a purely imaginary number, then \[z.\bar{z}\] is equal to

If \[\frac{z-i}{z+i}(z\ne -i)\] is a purely imaginary number, then \[z

1.	If \[\frac{z-i}{z+i}(z\ne -i)\] is a purely imaginary number, then \[z.\bar{z}\] is equal to
A.	0
B.	1
C.	2
D.	None of these
Answer» C. 2