If \[\frac{1}{a},\frac{1}{b},\frac{1}{c}\] are A. P., then \[\left( \frac{1}{a}+\frac{1}{b}-\frac{a}{c} \right)\] \[\left( \frac{1}{b}+\frac{1}{c}-\frac{1}{a} \right)\] is equal to

\[\frac{{{b}^{2}}-ac}{{{a}^{2}}{{b}^{2}}{{c}^{2}}}\]

\[\frac{4}{ac}-\frac{3}{{{b}^{2}}}\]

\[\frac{4}{ac}-\frac{1}{{{b}^{2}}}\]

If \[\frac{1}{a},\frac{1}{b},\frac{1}{c}\] are A. P., then \[\left( \f

1.	If \[\frac{1}{a},\frac{1}{b},\frac{1}{c}\] are A. P., then \[\left( \frac{1}{a}+\frac{1}{b}-\frac{a}{c} \right)\] \[\left( \frac{1}{b}+\frac{1}{c}-\frac{1}{a} \right)\] is equal to
A.	\[\frac{4}{ac}-\frac{3}{{{b}^{2}}}\]
B.	\[\frac{{{b}^{2}}-ac}{{{a}^{2}}{{b}^{2}}{{c}^{2}}}\]
C.	\[\frac{4}{ac}-\frac{1}{{{b}^{2}}}\]
D.	None of these
Answer» B. \[\frac{{{b}^{2}}-ac}{{{a}^{2}}{{b}^{2}}{{c}^{2}}}\]

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If \[\frac{1}{a},\frac{1}{b},\frac{1}{c}\] are A. P., then \[\left( \frac{1}{a}+\frac{1}{b}-\frac{a}{c} \right)\] \[\left( \frac{1}{b}+\frac{1}{c}-\frac{1}{a} \right)\] is equal to

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