1.

If \[\frac{\omega }{{{\omega }_{n}}}=\sqrt{2}\] where \[\omega \] is the frequency of excitation and \[{{\omega }_{n}}\] is the natural frequency of vibrations, then the transmissibility of vibrations will be:

A. 0.5
B. 1
C. 1.5
D. 2
Answer» C. 1.5


Discussion

No Comment Found

Related MCQs