If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.

\((\frac{x}{4})^2-(\frac{y}{3})^2\)=1

\((\frac{x}{3})^2-(\frac{y}{4})^2\)=1

\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1

\((\frac{x}{8})^2-(\frac{y}{6})^2\)=1

If foci of a hyperbola are (0, ±5) and length of semi transverse axis

1.	If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
A.	\((\frac{x}{4})^2-(\frac{y}{3})^2\)=1
B.	\((\frac{x}{3})^2-(\frac{y}{4})^2\)=1
C.	\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1
D.	\((\frac{x}{8})^2-(\frac{y}{6})^2\)=1
Answer» B.

If foci of a hyperbola are (0, ±5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
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