If \(f\left( x \right) = \frac{x}{2} - 1\), then on the interval [0, π] which one of the following is correct?

tan [f(x)], where [⋅] is the greatest integer function, is discontinuous but \(\frac{1}{{f\left( x \right)}}\) is continuous

tan [f(x)], where [⋅] is the greatest integer function, and \(\frac{1}{{f\left( x \right)}}\) are both continuous

tan [f(x)], where [⋅] is the greatest integer function, and f-1(x) are both continuous

tan [f(x)], where [⋅] is the greatest integer function, and \(\frac{1}{{f\left( x \right)}}\) are both discontinuous

If \(f\left( x \right) = \frac{x}{2} - 1\), then on the interval [0,

1.	If \(f\left( x \right) = \frac{x}{2} - 1\), then on the interval [0, π] which one of the following is correct?
A.	tan [f(x)], where [⋅] is the greatest integer function, and \(\frac{1}{{f\left( x \right)}}\) are both continuous
B.	tan [f(x)], where [⋅] is the greatest integer function, and f-1(x) are both continuous
C.	tan [f(x)], where [⋅] is the greatest integer function, and \(\frac{1}{{f\left( x \right)}}\) are both discontinuous
D.	tan [f(x)], where [⋅] is the greatest integer function, is discontinuous but \(\frac{1}{{f\left( x \right)}}\) is continuous
Answer» D. tan [f(x)], where [⋅] is the greatest integer function, is discontinuous but \(\frac{1}{{f\left( x \right)}}\) is continuous

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If \(f\left( x \right) = \frac{x}{2} - 1\), then on the interval [0, π] which one of the following is correct?

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