If f(x) = x2 – 153 = 0 then the iterative formula for Newton Raphso – McqOptions

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1.	If f(x) = x2 – 153 = 0 then the iterative formula for Newton Raphson Method is given by __________
A.	x(n+1) = 0.5 [x(n)+\(\frac{153}{x(n)}\)]
B.	x(n+1) = 0.5 [x(n)-\(\frac{153}{x(n)}\)]
C.	x(n+1) = [x(n)+\(\frac{153}{x(n)}\)]
D.	x(n+1) = [x(n)-\(\frac{153}{x(n)}\)]
Answer» B. x(n+1) = 0.5 [x(n)-\(\frac{153}{x(n)}\)]

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