If computer A has cycle ta = 250ps and cpl (cycles/inst) = 2.0 and computer B has cycle tb = 500ps and cpl = 1.2 then:

Computer B is 1.2 faster than A

Computer B is 2 times faster than B

Computer B is 2 times faster than A

Computer A is 1.2 times faster than B

If computer A has cycle ta = 250ps and cpl (cycles/inst) = 2.0 and com

1.	If computer A has cycle ta = 250ps and cpl (cycles/inst) = 2.0 and computer B has cycle tb = 500ps and cpl = 1.2 then:
A.	Computer B is 1.2 faster than A
B.	Computer B is 2 times faster than B
C.	Computer B is 2 times faster than A
D.	Computer A is 1.2 times faster than B
Answer» E.

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If computer A has cycle ta = 250ps and cpl (cycles/inst) = 2.0 and computer B has cycle tb = 500ps and cpl = 1.2 then:

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