If \[\alpha ,\beta \] be the roots of the equation \[{{x}^{2}}-2x+3=0\], then the equation whose roots are \[\frac{1}{{{\alpha }^{2}}}\]and \[\frac{1}{{{\beta }^{2}}}\] is

If \[\alpha ,\beta \] be the roots of the equation \[{{x}^{2}}-2x+3=0\

1.	If \[\alpha ,\beta \] be the roots of the equation \[{{x}^{2}}-2x+3=0\], then the equation whose roots are \[\frac{1}{{{\alpha }^{2}}}\]and \[\frac{1}{{{\beta }^{2}}}\] is
A.	\[{{x}^{2}}+2x+1=0\]
B.	\[9{{x}^{2}}+2x+1=0\]
C.	\[9{{x}^{2}}-2x+1=0\]
D.	\[9{{x}^{2}}+2x-1=0\]
Answer» C. \[9{{x}^{2}}-2x+1=0\]

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If \[\alpha ,\beta \] be the roots of the equation \[{{x}^{2}}-2x+3=0\], then the equation whose roots are \[\frac{1}{{{\alpha }^{2}}}\]and \[\frac{1}{{{\beta }^{2}}}\] is

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