If \[A=\left[ \begin{matrix} 2 & 2 \\ -3 & 2 \\ \end{matrix} \right]\] and \[B=\left[ \begin{matrix} 0 & -1 \\ 1 & 0 \\ \end{matrix} \right],\] then \[{{({{B}^{-1}}{{A}^{-1}})}^{-1}}\]= [EAMCET 2001]

\[\left[ \begin{matrix} 3 & -2 \\ 2 & 2 \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} 2 & -2 \\ 2 & 3 \\ \end{matrix} \right]\]

\[\frac{1}{10}\left[ \begin{matrix} 2 & 2 \\ -2 & 3 \\ \end{matrix} \right]\]

\[\frac{1}{10}\left[ \begin{matrix} 3 & 2 \\ -2 & 2 \\ \end{matrix} \right]\]

If \[A=\left[ \begin{matrix} 2 & 2 \\ -3 & 2 \\ \end{mat

1.	If \[A=\left[ \begin{matrix} 2 & 2 \\ -3 & 2 \\ \end{matrix} \right]\] and \[B=\left[ \begin{matrix} 0 & -1 \\ 1 & 0 \\ \end{matrix} \right],\] then \[{{({{B}^{-1}}{{A}^{-1}})}^{-1}}\]= [EAMCET 2001]
A.	\[\left[ \begin{matrix} 2 & -2 \\ 2 & 3 \\ \end{matrix} \right]\]
B.	\[\left[ \begin{matrix} 3 & -2 \\ 2 & 2 \\ \end{matrix} \right]\]
C.	\[\frac{1}{10}\left[ \begin{matrix} 2 & 2 \\ -2 & 3 \\ \end{matrix} \right]\]
D.	\[\frac{1}{10}\left[ \begin{matrix} 3 & 2 \\ -2 & 2 \\ \end{matrix} \right]\]
Answer» B. \[\left[ \begin{matrix} 3 & -2 \\ 2 & 2 \\ \end{matrix} \right]\]

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If \[A=\left[ \begin{matrix} 2 & 2 \\ -3 & 2 \\ \end{matrix} \right]\] and \[B=\left[ \begin{matrix} 0 & -1 \\ 1 & 0 \\ \end{matrix} \right],\] then \[{{({{B}^{-1}}{{A}^{-1}})}^{-1}}\]= [EAMCET 2001]

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