If \[A=\left[ \begin{matrix} 0 & 1 \\ 0 & 0 \\ \end{matrix} \right]\]and \[AB=O\], then B = [MP PET 1989]

\[\left[ \begin{matrix} 1 & 1 \\ 1 & 1 \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} 0 & 1 \\ -1 & 0 \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} 0 & -1 \\ 1 & 0 \\ \end{matrix} \right]\]

\[\left[ \begin{matrix} -1 & 0 \\ 0 & 0 \\ \end{matrix} \right]\]

If \[A=\left[ \begin{matrix} 0 & 1 \\ 0 & 0 \\ \end{matr

1.	If \[A=\left[ \begin{matrix} 0 & 1 \\ 0 & 0 \\ \end{matrix} \right]\]and \[AB=O\], then B = [MP PET 1989]
A.	\[\left[ \begin{matrix} 1 & 1 \\ 1 & 1 \\ \end{matrix} \right]\]
B.	\[\left[ \begin{matrix} 0 & 1 \\ -1 & 0 \\ \end{matrix} \right]\]
C.	\[\left[ \begin{matrix} 0 & -1 \\ 1 & 0 \\ \end{matrix} \right]\]
D.	\[\left[ \begin{matrix} -1 & 0 \\ 0 & 0 \\ \end{matrix} \right]\]
Answer» E.

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If \[A=\left[ \begin{matrix} 0 & 1 \\ 0 & 0 \\ \end{matrix} \right]\]and \[AB=O\], then B = [MP PET 1989]

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