If a circle passes through the point (1, 2) and cuts the circle \[{{x}^{2}}+{{y}^{2}}=4\] orthogonally, then the equation of the locus of its centre is [MNR 1992]

\[{{x}^{2}}+{{y}^{2}}-3x-8y+1=0\]

\[{{x}^{2}}+{{y}^{2}}-2x-6y-7=0\]

If a circle passes through the point (1, 2) and cuts the circle \[{{x}

1.	If a circle passes through the point (1, 2) and cuts the circle \[{{x}^{2}}+{{y}^{2}}=4\] orthogonally, then the equation of the locus of its centre is [MNR 1992]
A.	\[{{x}^{2}}+{{y}^{2}}-3x-8y+1=0\]
B.	\[{{x}^{2}}+{{y}^{2}}-2x-6y-7=0\]
C.	\[2x+4y-9=0\]
D.	\[2x+4y-1=0\]
Answer» D. \[2x+4y-1=0\]

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If a circle passes through the point (1, 2) and cuts the circle \[{{x}^{2}}+{{y}^{2}}=4\] orthogonally, then the equation of the locus of its centre is [MNR 1992]

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