1.

If A=\(\begin{bmatrix}2\\7\\8\end{bmatrix}\), B=\(\begin{bmatrix}-3&4&1\end{bmatrix}\), find (AB)’.

A. (AB)’=\(\begin{bmatrix}-6&-21&-24\\8&28&32\\2&7&8\end{bmatrix}\)
B. (AB)’=\(\begin{bmatrix}-6&8&2\\-21&-28&7\\-24&32&8\end{bmatrix}\)
C. (AB)’=\(\begin{bmatrix}6&21&24\\-8&28&7\\-2&7&-8\end{bmatrix}\)
D. (AB)’=\(\begin{bmatrix}-6&8&-21\\8&2&7\\-24&8&2\end{bmatrix}\)
Answer» B.


Discussion

No Comment Found