If a + b + c = 0, then one of the solutions of\(\left| {\begin{array}{*{20}{c}} {a - x}&c&b\\ c&{b - x}&a\\ b&a&{c - x} \end{array}} \right| = 0\) is

\(x = \sqrt {\frac{{3\left( {{a^2} + {b^2} + {c^2}} \right)}}{2}} \)

\(x = \sqrt {\frac{{2\left( {{a^2} + {b^2} + {c^2}} \right)}}{3}} \)

If a + b + c = 0, then one of the solutions of\(\left| {\begin{array}{

1.	If a + b + c = 0, then one of the solutions of\(\left\| {\begin{array}{*{20}{c}} {a - x}&c&b\\ c&{b - x}&a\\ b&a&{c - x} \end{array}} \right\| = 0\) is
A.	x = a
B.	\(x = \sqrt {\frac{{3\left( {{a^2} + {b^2} + {c^2}} \right)}}{2}} \)
C.	\(x = \sqrt {\frac{{2\left( {{a^2} + {b^2} + {c^2}} \right)}}{3}} \)
D.	x = 0
Answer» E.

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If a + b + c = 0, then one of the solutions of\(\left| {\begin{array}{*{20}{c}} {a - x}&c&b\\ c&{b - x}&a\\ b&a&{c - x} \end{array}} \right| = 0\) is

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