If \(6\frac{3}{x}\times y\frac{2}{3}=30~and~2\frac{1}{2}-3\frac{2}{3}+1\frac{5}{6}-\frac{2}{z}=0\) where x, y and z are positive integers and the fractions are in the lowest terms, then the value of (x + y – z) is∶

• A. 8
• B. 0
• C. 10
• D. 11