If \(1^2 +2^2 +3^2 + ...+n^2 = \dfrac{n(n+1)(2n+1)}{6},\) find the v – McqOptions

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1.	If \(1^2 +2^2 +3^2 + ...+n^2 = \dfrac{n(n+1)(2n+1)}{6},\) find the value of \(5^2 +6^2 + 7^2 + ....+10^2.\)
A.	330
B.	345
C.	355
D.	360
Answer» D. 360

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