Hall-Heroult’s process is given by

• A. \(ZnO+C\xrightarrow[]{coke,1673K}Zn+CO\)
• B. Cr2O3 + 2Al ⟶ Al2O3 + 2Cr
• C. 2Al2O3 + 3C ⟶ 4Al + 3CO2
• D. Cu2+ (aq) + H2 (g) ⟶ Cu (s) + 2H+ (aq)