Given the equilibrium constant (Kc) of the reaction:Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) is 10 × 1015, calculate the \(E{^\circ _{cell}}\) of this reaction at 298 K.\(\left[ {2.303\frac{{RT}}{F}at\;298\;K = 0.059\;V} \right]\)

Given the equilibrium constant (Kc) of the reaction:Cu(s) + 2Ag+ (aq)

1.	Given the equilibrium constant (Kc) of the reaction:Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) is 10 × 1015, calculate the \(E{^\circ _{cell}}\) of this reaction at 298 K.\(\left[ {2.303\frac{{RT}}{F}at\;298\;K = 0.059\;V} \right]\)
A.	0.4736 V
B.	0.4736 mV
C.	0.4736 Mv
D.	0.04736 V
Answer» B. 0.4736 mV