MCQOPTIONS
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| 1. |
Given that m = mass of the ball of the governor, \[\omega \,\,=\] angular velocity of the governor and g = accelerate due to gravity, The height of Watt's governor is given by: |
| A. | \[\frac{g}{2{{\omega }^{2}}}\] |
| B. | \[\frac{g}{{{\omega }^{2}}}\] |
| C. | \[\frac{\sqrt{2g}}{{{\omega }^{2}}}\] |
| D. | \[\frac{g}{{{\omega }^{2}}}\] |
| Answer» C. \[\frac{\sqrt{2g}}{{{\omega }^{2}}}\] | |