Given f (x,y)=sin⁡xy, what is the value of the third degree first term in Taylor’s series near (1,-$\frac{π}{2}$) where it is expanded in increasing order of degree & by following algebraic identity rule?

Question

Given f (x,y)=sin⁡xy, what is the value of the  third degree first term in Taylor’s series near (1,-$\frac{π}{2}$) where it is expanded in increasing order of degree & by following algebraic identity rule?

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{π^3}{8}$

TuteeHUB · Answer

$\frac{π^3}{8} \frac{(x-1)(y+\frac{π}{2})}{3!}$

TuteeHUB · Answer

$-\frac{π^3}{8} \frac{(x-1)^3}{3!}$

1.	Given f (x,y)=sin⁡xy, what is the value of the third degree first term in Taylor’s series near (1,-\(\frac{π}{2}\)) where it is expanded in increasing order of degree & by following algebraic identity rule?
A.	\(\frac{π^3}{8}\)
B.	\(\frac{π^3}{8} \frac{(x-1)(y+\frac{π}{2})}{3!}\)
C.	0
D.	\(-\frac{π^3}{8} \frac{(x-1)^3}{3!}\)
Answer» D.

Given f (x,y)=sin⁡xy, what is the value of the third degree first term in Taylor’s series near (1,-\(\frac{π}{2}\)) where it is expanded in increasing order of degree & by following algebraic identity rule?

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