Given a real valued function y (t) with period T. Its trigonometric Fourier series expansion contains no term of frequency ω = 2π $\frac{(2k)}{T}$; where, k = 1, 2….. Also no terms are present. Then, y(t) satisfies the equation ____________

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

y (t) = y (t+T) = -y (t+$\frac{T}{2}$)

TuteeHUB · Answer

y (t) = y (t+T) = y (t+$\frac{T}{2}$)

TuteeHUB · Answer

y (t) = y (t-T) = -y (t-$\frac{T}{2}$)

TuteeHUB · Answer

y (t) = y (t-T) = y (t-$\frac{T}{2}$)

1.	Given a real valued function y (t) with period T. Its trigonometric Fourier series expansion contains no term of frequency ω = 2π \(\frac{(2k)}{T}\); where, k = 1, 2….. Also no terms are present. Then, y(t) satisfies the equation ____________
A.	y (t) = y (t+T) = -y (t+\(\frac{T}{2}\))
B.	y (t) = y (t+T) = y (t+\(\frac{T}{2}\))
C.	y (t) = y (t-T) = -y (t-\(\frac{T}{2}\))
D.	y (t) = y (t-T) = y (t-\(\frac{T}{2}\))
Answer» E.

Given a real valued function y (t) with period T. Its trigonometric Fourier series expansion contains no term of frequency ω = 2π \(\frac{(2k)}{T}\); where, k = 1, 2….. Also no terms are present. Then, y(t) satisfies the equation ____________

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