f(x, y)=\(\frac{x^3+y^3}{x^{99}+y^{98}x+y^{99}}\) find the value of f – McqOptions

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1.	f(x, y)=\(\frac{x^3+y^3}{x^{99}+y^{98}x+y^{99}}\) find the value of fy at (x,y) = (0,1).
A.	101
B.	-96
C.	210
D.	0
Answer» C. 210

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