\[\frac{1}{\tan 3A-\tan A}-\frac{1}{\cot 3A-\cot A}=\]

1.	\[\frac{1}{\tan 3A-\tan A}-\frac{1}{\cot 3A-\cot A}=\]
A.	\[\tan A\]
B.	\[\tan 2A\]
C.	\[\cot A\]
D.	\[\cot 2A\]
Answer» E.

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\[\frac{1}{\tan 3A-\tan A}-\frac{1}{\cot 3A-\cot A}=\]

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