For the following cell reaction \[Pb(s)+H{{g}_{2}}S{{O}_{4}}(s)PbS{{O}_{4}}(s)+2Hg(l)\] \[E_{cell}^{o}=0.92V\] \[{{K}_{sp}}(PbS{{O}_{4}})=2\times {{10}^{-8}},\]\[{{K}_{sp}}(H{{g}_{2}}S{{O}_{4}})=1\times {{10}^{-6}}\] Hence, \[{{E}_{cell}}\] is

For the following cell reaction \[Pb(s)+H{{g}_{2}}S{{O}_{4}}(s)PbS{{O}

1.	For the following cell reaction \[Pb(s)+H{{g}_{2}}S{{O}_{4}}(s)PbS{{O}_{4}}(s)+2Hg(l)\] \[E_{cell}^{o}=0.92V\] \[{{K}_{sp}}(PbS{{O}_{4}})=2\times {{10}^{-8}},\]\[{{K}_{sp}}(H{{g}_{2}}S{{O}_{4}})=1\times {{10}^{-6}}\] Hence, \[{{E}_{cell}}\] is
A.	0.92 V
B.	0.89 V
C.	1.04 V
D.	0.95 V
Answer» E.

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For the following cell reaction \[Pb(s)+H{{g}_{2}}S{{O}_{4}}(s)PbS{{O}_{4}}(s)+2Hg(l)\] \[E_{cell}^{o}=0.92V\] \[{{K}_{sp}}(PbS{{O}_{4}})=2\times {{10}^{-8}},\]\[{{K}_{sp}}(H{{g}_{2}}S{{O}_{4}})=1\times {{10}^{-6}}\] Hence, \[{{E}_{cell}}\] is

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